stathomeworkhelper1234.com
1234.com 时间:2021-04-06 阅读:()
5.
2.
notebook1August06,2015Aug89:26AM5.
2HowCanWeFindProbabilitiesAug89:26AMLearningObjectivesSampleSpaceEventProbabilitiesforandofSamplespaceEventPairofeventsUnionoftwoeventsIntersectionoftwoeventsmatthewwmason.
files.
wordpress.
comAug89:26AMSampleSpaceSampleSpace–setofallpossibleoutcomesEvent-Subsetofsamplespace,correspondingtooneoragroupofoutcomesAug89:26AMSampleSpaceForarandomphenomenon,thesamplespaceisthesetofallpossibleoutcomes.
SampleSpace:Events:EventA:All3correct=EventB:Atleast2correct=Aug89:26AMExample:WhataretheChancesofbeingAuditedFindtheProbabilityofbeingauditedFindtheprobabilityofanincomegreatertha$100,000Aug89:26AMProbabilitiesforaSampleSpaceEachoutcomehasaprobabilityAllprobabilityisbetween0and1Sumofallprobabilitiesis1www.
stathomeworkhelper.
com0=1=P(Heads)=P(Tails)=P(H)+P(T)=5.
2.
notebook2August06,2015Aug89:26AMProbabilityofanEventProbabilityofeventA,P(A),issumofoutcomeprobabilitiesineventWhenalloutcomesareequallylikely:www.
georgiamath1234.
comP(A)=SpecificTotalP(R)=P(B)=P(Yc)=Aug89:26AMProbabilityRulesofPairsofEventsUnion:ORIneitherorbotheventsIntersection:ANDInbotheventsComplement:NOTNotintheeventIntersectionofAandB:A&BUnionofAandB:AorBComplementofA:ACAug89:26AMComplementofEventAAlloutcomesinsamplespacenotinAP(A)+P(Ac)=1So,P(Ac)=1–P(A)P(A)=1P(Ac)Aug89:26AMDisjointEventsAandBaredisjointiftheyhavenocommonoutcomesDisjointExampleDice:Even#'s=Odd#'s=NotDisjointExampleCards:Hearts=Kings=Aug89:26AMProbabilityofUnionofTwoEventsAdditionRulefortheunionofanytwoevents,P(AorB)=P(A)+P(B)–P(AandB)Mar259:54AMIfdisjoint,P(AandB)=0,soP(AorB)=P(A)+P(B)Unionof2DisjointEvents5.
2.
notebook3August06,2015Mar259:57AMP(HeartorKing)=DisjointCardsProblemMar259:57AMP(Even#or3)=DiceProblemDisjointAug89:26AMFindtheprobabilityofbeingauditedorhavinganincomegreaterthat$100,000ChancesofBeingAuditedAug89:26AMMultiplicationRulefortwoseparateindependentevents,AandB,P(AandB)=P(A)xP(B)ProbabilityofIntersectionofTwoEventsIndependent(2separateevents):P(rolla3andfliptails)=1eventusingthewordAND:P(heartandaking)=Mar2510:04AMFindtheprobabilityofbeingauditedandhavinganincomegreaterthan$100,000Aug89:26AMTreeGraphExamplesIftheprobabilityofguessingcorrectlyis.
2Whatistheprobabilityofgetting3questionscorrectbyguessingWhatistheprobabilitythatastudentanswersatleast2questionscorrectly5.
2.
notebook4August06,2015Mar2610:22AMThecomplementof"atleast1"=0Ifyouflipacoin10times.
Whatistheprobabilityyougetatleast1tailsAug89:26AMAssumingIndependenceDon'tassumeindependence!
IndependenceTestIf:P(AandB)=P(A)XP(B)Then:AandBareindependentMar268:39AMAregettingthe1standthe2ndquestioncorrectindependenteventsA=1stcorrectB=2ndcorrectP(A)=CC+CI=P(B)=CC+IC=P(AandB)=P(AandB)=P(A)xP(B)Aug89:26AMAug143:22PM
2.
notebook1August06,2015Aug89:26AM5.
2HowCanWeFindProbabilitiesAug89:26AMLearningObjectivesSampleSpaceEventProbabilitiesforandofSamplespaceEventPairofeventsUnionoftwoeventsIntersectionoftwoeventsmatthewwmason.
files.
wordpress.
comAug89:26AMSampleSpaceSampleSpace–setofallpossibleoutcomesEvent-Subsetofsamplespace,correspondingtooneoragroupofoutcomesAug89:26AMSampleSpaceForarandomphenomenon,thesamplespaceisthesetofallpossibleoutcomes.
SampleSpace:Events:EventA:All3correct=EventB:Atleast2correct=Aug89:26AMExample:WhataretheChancesofbeingAuditedFindtheProbabilityofbeingauditedFindtheprobabilityofanincomegreatertha$100,000Aug89:26AMProbabilitiesforaSampleSpaceEachoutcomehasaprobabilityAllprobabilityisbetween0and1Sumofallprobabilitiesis1www.
stathomeworkhelper.
com0=1=P(Heads)=P(Tails)=P(H)+P(T)=5.
2.
notebook2August06,2015Aug89:26AMProbabilityofanEventProbabilityofeventA,P(A),issumofoutcomeprobabilitiesineventWhenalloutcomesareequallylikely:www.
georgiamath1234.
comP(A)=SpecificTotalP(R)=P(B)=P(Yc)=Aug89:26AMProbabilityRulesofPairsofEventsUnion:ORIneitherorbotheventsIntersection:ANDInbotheventsComplement:NOTNotintheeventIntersectionofAandB:A&BUnionofAandB:AorBComplementofA:ACAug89:26AMComplementofEventAAlloutcomesinsamplespacenotinAP(A)+P(Ac)=1So,P(Ac)=1–P(A)P(A)=1P(Ac)Aug89:26AMDisjointEventsAandBaredisjointiftheyhavenocommonoutcomesDisjointExampleDice:Even#'s=Odd#'s=NotDisjointExampleCards:Hearts=Kings=Aug89:26AMProbabilityofUnionofTwoEventsAdditionRulefortheunionofanytwoevents,P(AorB)=P(A)+P(B)–P(AandB)Mar259:54AMIfdisjoint,P(AandB)=0,soP(AorB)=P(A)+P(B)Unionof2DisjointEvents5.
2.
notebook3August06,2015Mar259:57AMP(HeartorKing)=DisjointCardsProblemMar259:57AMP(Even#or3)=DiceProblemDisjointAug89:26AMFindtheprobabilityofbeingauditedorhavinganincomegreaterthat$100,000ChancesofBeingAuditedAug89:26AMMultiplicationRulefortwoseparateindependentevents,AandB,P(AandB)=P(A)xP(B)ProbabilityofIntersectionofTwoEventsIndependent(2separateevents):P(rolla3andfliptails)=1eventusingthewordAND:P(heartandaking)=Mar2510:04AMFindtheprobabilityofbeingauditedandhavinganincomegreaterthan$100,000Aug89:26AMTreeGraphExamplesIftheprobabilityofguessingcorrectlyis.
2Whatistheprobabilityofgetting3questionscorrectbyguessingWhatistheprobabilitythatastudentanswersatleast2questionscorrectly5.
2.
notebook4August06,2015Mar2610:22AMThecomplementof"atleast1"=0Ifyouflipacoin10times.
Whatistheprobabilityyougetatleast1tailsAug89:26AMAssumingIndependenceDon'tassumeindependence!
IndependenceTestIf:P(AandB)=P(A)XP(B)Then:AandBareindependentMar268:39AMAregettingthe1standthe2ndquestioncorrectindependenteventsA=1stcorrectB=2ndcorrectP(A)=CC+CI=P(B)=CC+IC=P(AandB)=P(AandB)=P(A)xP(B)Aug89:26AMAug143:22PM
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