求导 三角函数y=2sin((x+1-x+1)/2)cos(((x+1+x-1)/2)/2sin((x+2-x+2)/2)cos(((x+2+x-2)/2) =sin1/sin2 y的导数是0...
三角函数的导数问题两边求导：dy/dx×sin(x^2)＋y×2xcos(x^2)＝sin(y^2)＋x×2ycos(y^2)×dy/dx dy/dx＝[2xycos(x^2)－sin(y^2)] / [2xycos(y^2)－sin(x^2)]...