httpclientpost怎么使用httpclient post接收xml文件

如何使用httpclient进行post请求

http请求传递的都是字符串。

这种情况一般使用xml为信息载体。

把java类转成xml, client得到xml再转成java类。

UserDTO user = new UserDTO(); ...//填充user XStream xstream = new XStream();//使用xstream转换pojo和xml字符串 // HttpPost连接...

HttpClient的Post方法要怎么使用？

HttpClient client = new DefaultHttpClient(); HttpPost post = new HttpPost(URL); List params = new ArrayList(); String toServer = youdata; params.add(new BasicNameValuePair("par", "toServer")); try { HttpEntity httpentity = new UrlEncodedFormEntity(params,"gb2312"); post.setEntity(httpentity); HttpResponse httpResponse = client.execute(post); if(httpResponse.getStatusLine().getStatusCode() == HttpStatus.SC_OK) { //处理POST返回回来的数据 } } catch (ClientProtocolException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); }

httpclient中怎么使用post方法获取html的源码

public void clientPost() { String httpUrl="http://10.0.2.2:8080/JDemo/android/httpget2.jsp"; // HttpPost连接对象 HttpPost httpRequest=new HttpPost(httpUrl); //使用NameValuePair来保存要传递的Post参数 List params=new ArrayList(); //添加要传递的参数 params.add(new BasicNameValuePair("par","HTTP_Client_android_Post")); try { //设置字符集 HttpEntity httpentity=new UrlEncodedFormEntity(params,"gb2312"); //请求httpRequest httpRequest.setEntity(httpentity); //取得HttpClient对象 HttpClient httpclient=new DefaultHttpClient(); //请求HttpCLient，取得HttpResponse HttpResponse httpResponse=httpclient.execute(httpRequest); //请求成功 if(httpResponse.getStatusLine().getStatusCode()==HttpStatus.SC_OK) { //取得返回的字符串 String strResult=EntityUtils.toString(httpResponse.getEntity()); text1.setText(strResult.trim()); }else { text1.setText("请求错误！"); } } catch (ClientProtocolException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); }catch(Exception e) { text1.setText(e.getMessage().toString()); } } 纯手打，望采纳！

httpclient中post命令需要的参数从哪里得知？

对应的变量名你还是问问网站的工作人员吧，点击某个按钮你可以将信息先传到servlet，在servlet里面引用httpclient，很简单的。

具体还是参考一下HttpClient类的executeMethod方法吧，网上一堆，多多练习，祝你好运

httpclient可以post文件吗

//?Java?使用HttpClient?post文件实现代码 import?java.io.File; .apache.http.HttpEntity; .apache.http.HttpResponse; .apache.http.HttpVersion; .apache.http.client.HttpClient; .apache.http.client.methods.HttpPost; .apache.http.entity.mime.MultipartEntity; .apache.http.entity.mime.content.ContentBody; .apache.http.entity.mime.content.FileBody; .apache.http.impl.client.DefaultHttpClient; .apache.http.params.CoreProtocolPNames; .apache.http.util.EntityUtils; public?class?PostFile?{ ??public?static?void?main(String[]?args)?throws?Exception?{ ????HttpClient?httpclient?=?new?DefaultHttpClient(); ????httpclient.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION,?HttpVersion.HTTP_1_1); ????HttpPost?httppost?=?new?HttpPost("http://localhost:9001/upload.php"); ????File?file?=?new?File("c:/TRASH/zaba_1.jpg"); ????MultipartEntity?mpEntity?=?new?MultipartEntity(); ????ContentBody?cbFile?=?new?FileBody(file,?"image/jpeg"); ????mpEntity.addPart("userfile",?cbFile); ????httppost.setEntity(mpEntity); ????System.out.println("executing?request?"?+?httppost.getRequestLine()); ????HttpResponse?response?=?httpclient.execute(httppost); ????HttpEntity?resEntity?=?response.getEntity(); ????System.out.println(response.getStatusLine()); ????if?(resEntity?!=?null)?{ ??????System.out.println(EntityUtils.toString(resEntity)); ????} ????if?(resEntity?!=?null)?{ ??????resEntity.consumeContent(); ????} ????httpclient.getConnectionManager().shutdown(); ??} }

怎么使用httpclient post接收xml文件

现在sql2005可以直接接受xml数据，只要你逻辑层，把表示层数据构造好xml文件，直接提交到相应的xml字段就可以 using System; using System.Collections.Generic; using System.IO; using System.Text; using System.Net; using System.Web; namespace Deerchao.Utility { public class HttpClient { #region fields private bool keepContext; private string defaultLanguage = "zh-CN"; private Encoding defaultEncoding = Encoding.UTF8; private string ept = "*/*"; private string userAgent = "Mozilla/4.0 patible; MSIE 6.0; Windows NT 5.2; SV1; .NET CLR 1.1.4322; .NET CLR 2.0.50727)"; private HttpVerb verb = HttpVerb.GET; private HttpClientContext context; private readonly List files = new List(); private readonly Dictionary postingData = new Dictionary(); private string url; private WebHeaderCollection responseHeaders; private int startPoint; private int endPoint; #endregion